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5x^2-17x+3=-4x-5
We move all terms to the left:
5x^2-17x+3-(-4x-5)=0
We get rid of parentheses
5x^2-17x+4x+5+3=0
We add all the numbers together, and all the variables
5x^2-13x+8=0
a = 5; b = -13; c = +8;
Δ = b2-4ac
Δ = -132-4·5·8
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-3}{2*5}=\frac{10}{10} =1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+3}{2*5}=\frac{16}{10} =1+3/5 $
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